(v+2)^2(v-1)=9(v-1)

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Solution for (v+2)^2(v-1)=9(v-1) equation: 



(v+2)^2(v-1)=9(v-1)

We move all terms to the left:

(v+2)^2(v-1)-(9(v-1))=0



We calculate terms in parentheses: -(9(v-1)), so:

9(v-1)

We multiply parentheses

9v-9

Back to the equation:

-(9v-9)



We get rid of parentheses

(v+2)^2(v-1)-9v+9=0

We add all the numbers together, and all the variables

-9v+(v+2)^2(v-1)+9=0

We move all terms containing v to the left, all other terms to the right

-9v+(v+2)^2(v-1)=-9

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